Posted by **madison** on Wednesday, July 3, 2013 at 1:27am.

A gas has a pressure of 0.370 atm at 50.0 °C. What is the pressure at 22 °C, assuming volume remains constant?

- chemistry -
**Jai**, Wednesday, July 3, 2013 at 7:30am
Assuming the gas is ideal, we use Gay-Lussac's Law to relate the relationship between Temperature & Pressure of gas:

P1/T1 = P2/T2

where:

T1 = initial temperature of gas (in K)

T2 = final temperature of gas (in K)

P1 = initial pressure of gas

P2 = final pressure of gas

*note that to convert Celsius to Kelvin, we just add 273.

substituting,

(0.370)/(50+273) = P2/(22+273)

P2 = (0.370)(323)/295

P2 = ?

now solve for P2. units in atm.

hope this helps~ :)

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