Posted by **Inkiena** on Tuesday, July 2, 2013 at 10:09pm.

sand is falling into a conical pile so that the radius of the base of the pile is always equal to one half its altitude. of the sand is falling at the rate of 10 cubic feet per minute, how fast is the altitude of the pile increasing when the pile is 5 feet deep?

- Calculus -
**Reiny**, Tuesday, July 2, 2013 at 10:59pm
given: r = h/2

V = (1/3)π r^2 h

= (1/3)π (h/2)^2 (h)

= (1/12) π h^3

dV/dt = (1/4)π h^2 dh/dt

for the given data ...

10 = (1/4)π(25)dh/dt

dh/dt = 10(4)/((25π) = 1.6/π feet/min

check my arithmetic

- Calculus -
**Anonymous**, Wednesday, January 14, 2015 at 12:31am
LOL

- Calculus -
**Anonymous**, Sunday, December 13, 2015 at 8:40pm
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