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January 31, 2015

January 31, 2015

Posted by **Meg** on Tuesday, July 2, 2013 at 4:31pm.

This is what I have so far

Presuming two fair, 6-sided dice, each numbered 1 through 6:

You can achieve one of the following results on any given roll: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12. But there is only 1 way to get a 2, 2 ways to get a 3, 3 ways to get a 4, up to 6 ways to get a 7, then 5 ways to get 8, and so on. Total is 1 + 2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1 = 36 possible outcomes.

The prime numbers from 2 through 12 inclusive are: 2, 3, 5, 7, and 11. There is 1 way to get a 2, 2 ways for a 3, 4 ways for a 5, 6 ways for a 7 and 2 ways for 11. Total of 1 + 2 + 4 + 6 + 2 = 15 successful outcomes out of 36 possible outcomes.

- Statistics -
**MathMate**, Tuesday, July 2, 2013 at 8:05pmYour reasoning and calculations are correct. So the probability of getting a prime number as the sum is 15/36.

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