# Physics

posted by
**Danny** on
.

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced.

ANS 1 = kPa (Round to 3 decimal places)

ANS 2 = (Round to 6 decimal places)

Bar length = 1.000m

Area = 10cm = 0.10m

Load = 5754.000N

Bar extension = 2.740mm = 0.002740m

Stress = Load/ Area

Strain = Change in length/ length

Stress = 5750.000N/ 0.10m

= 575000Pa

ANS = 575.000kPa

Strain = 0.002740/ 1

ANS = 0.002740

Please check. Thank you.