Tuesday

July 29, 2014

July 29, 2014

Posted by **Help** on Tuesday, July 2, 2013 at 5:10am.

2 (sec x)^2 + (tan x)^2 -3 = 0

- Pre-cal -
**Steve**, Tuesday, July 2, 2013 at 9:44amsince sec^2 x = 1+tan^2 x, we have

2(1+tan^2 x)+tan^2 x-3=0

3tan^2 x-1 = 0

tan^2 x = 1/3

tan x = ±1/√3

tan x > 0 in QI, QIII, so

x = π/6, 7π/6

tan x < 0 in QII, QIV, so

x = 5π/6, 11π/6

Actually, since the period of tan x is

π, it would be better to ask for solutions in [0,π) rather than 2π.

**Related Questions**

Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...

Pre-cal/Trig - (tan/(1+sec)) + ((1+sec)/tan) = 2csc (Show all work please.)

pre cal 2 - Find all solutions in the unterval [0,2pi), cos x/2-sinx=0

pre cal - Find all solutions in the interval[0,2pi),cos x/2-sinx=0

pre cal 2 - Find all solutions in the interval [0, pi], 2sec^2x+tan^2x-3=0

pre cal 2 - Find all solutions in the interval [0, pi], 2sec^2x+tan^2x-3=0

pre cal 2 - Find all solutions in the interval [0, pi], 2sec^2x+tan^2x-3=0

Pre-Cal - Perform the addition or subtraction. tanx - sec^2x/tanx tan^2(x)/tan(x...

Pre-Cal - Simplify the expression 1/tan^2x+1 tan^2x+1 = sec^2x = 1/sec^2x I am ...

Pre-Cal - Approximate the equation's soultions in the interval (o, 2pi). If ...