physics
posted by justin on .
A 34.1 kg child rides a Ferris wheel whose diameter is 18.3 m. When the ride is turning at a constant rate, the child’s speed has a constant value of 4.23 m/s. Find the normal force the seat exerts on the child at:
a) The top of the ride
b) The bottom of the ride

a= v²/R.
top
ma= mg –N
N=m(ga) =
=m (g v²/R) =
= 34.1{9.8  (4.23²/9.15 )}=
=267 N.
bottom
ma=Nmg
N= m(g+a) =
= m (g+ v²/R) =
= 34.1{9.8 +(4.23²/9.15 )}=
=401 N