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Posted by on Monday, July 1, 2013 at 4:27pm.

A 950-kg race car can drive around an unbanked turn at a maximum speed of 46 m/s without slipping. The turn has a radius of 120 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 12000 N on the car. (a) What is the coefficient of static friction between the track and the car's tires? (b) What would be the maximum speed if no downforce acted on the car?

  • physics - , Sunday, March 8, 2015 at 2:42pm

    a) μ = Fc/FN (i)
    FN =(950x9.8)+12000= 21310
    Fc =(950)(46)^2/120= 16751
    Putting values in (i) μ=0.7860 (no unit)

    b) v= sqrt(rμg)= sqrt[(120)(0.7860)(9.8)]
    v= 30.40 m/s^2

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