Post a New Question

physics

posted by on .

A 950-kg race car can drive around an unbanked turn at a maximum speed of 46 m/s without slipping. The turn has a radius of 120 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 12000 N on the car. (a) What is the coefficient of static friction between the track and the car's tires? (b) What would be the maximum speed if no downforce acted on the car?

  • physics - ,

    a) μ = Fc/FN (i)
    FN =(950x9.8)+12000= 21310
    Fc =(950)(46)^2/120= 16751
    Putting values in (i) μ=0.7860 (no unit)

    b) v= sqrt(rμg)= sqrt[(120)(0.7860)(9.8)]
    v= 30.40 m/s^2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question