Post a New Question


posted by .

the man hanging upside down is holding a partner who weighs 491 N. Assume that the partner moves on a circle that has a radius of 5.09 m. At a swinging speed of 4.20 m/s, what force must the man apply to his partner in the straight-down position?

  • physics -

    Weight =W= mg
    m=W/g =491 / 9.8 =50.1 kg

    F = mv²/ r=173.6
    =50.1•4.2²/5.09 = 173.6 N
    since his partner is in the straight-down position, the man also has to apply force to keep his partner from falling down due to gravity, so you have to add the partner's weight:
    Force total = 173.6 + 491 = 664.6 N

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question