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February 27, 2015

February 27, 2015

Posted by **anu** on Monday, July 1, 2013 at 7:53am.

- maths -
**Steve**, Monday, July 1, 2013 at 10:05amLet the number of cakes be a,b,c,d,e,f,g for the 7 children

a-(b+c+d+e+f+g) = 4

b+(2*6) = a-3

we want c+d+e+f+g. Call it x

a-b-x = 4

b+12 = a-3

x = (a-b)-4

a-b = 15

So, x = 11

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