Math
posted by Jazzy on .
A particular bacterium is found to have a doubling time of 20 minutes. If a laboratory begins with a population of 300 of these bacteria, and there is no change in the growth rate, how many bacteria will be present in 55 minutes?

I expect about 8 times as many, since 55 min is about 3 halflives.
p(t) = 300*2^(t/20)
so,
p(55) = 300*2^(55/20) = ?