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Calc I

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How do I find the derivative for the sqrt(sin(e^(x^3)*cos(x)))???

I know this is a combination of the chain rule and product rule. Please help!

  • Calc I - ,

    Nothing?

  • Calc I - ,

    You know, if no one responds right away, a better follow-up would be to show whatever ideas you have had in the meantime, rather than just tapping your foot and saying "nothing?".

    Your first thought, on seeing a complicated formula should have been the chain rule. what functions u and v could you use?

    y = √u where
    u = sin(e^(x^3)*cos(x))

    u = sin v
    where v = e^(x^3)*cos(x)

    Now you can work with things:

    y' = 1/2√u u'
    = 1/2√u cos v v'
    Now use the product rule:
    = 1/2√u cos v e^(x^3) (3x^2 cosx - x^3 sinx)

    Now just substitute back in for u and v.

  • Calc I - ,

    Thanks for your response. I was hardly taping my foot. I have been working on this problem for almost 6 days and by the time I posted this, I was over it. So I apologize if it seemed like I was impatient.

  • Calc I/STEVE!!! - ,

    You are the man!!!! I had tried this problem freaking 74 times. I had too many parenthesis, I forgot to add (e^(x^3)), and finally at the end of the derivative I did NOT include X^3 in front of sin(x).

    Thank youuuuuuuu

  • Calc I - ,

    Good work. Many many times it is easier to make a few simple substitutions to avoid all the punctuation. Even the most complex problems contain simple parts.

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