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Posted by Anonymous on Sunday, June 30, 2013 at 3:53pm.

solve the following logarithmic equation: 2lnx= log base e^3 343

log base e^3 = 1/3 ln, so 2lnx = ln e^2 1/3 ln 343 = ln ∛343 = ln ln7 x^2 = 7 x = √7

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