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December 17, 2014

December 17, 2014

Posted by **Anonymous** on Sunday, June 30, 2013 at 3:53pm.

2lnx= log base e^3 343

- precalc -
**Steve**, Sunday, June 30, 2013 at 5:25pmlog base e^3 = 1/3 ln, so

2lnx = ln e^2

1/3 ln 343 = ln ∛343 = ln ln7

x^2 = 7

x = √7

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