Posted by jovahnna on Sunday, June 30, 2013 at 3:44pm.
Factor completely: 3x^2(4x2 + 1)^8 + 64x^4(4x2 + 1)^7.
pre cal - Tony, Sunday, June 30, 2013 at 3:59pm
pre cal - jovahnna, Sunday, June 30, 2013 at 4:01pm
how did you solve this??? I am so los.
pre cal - Steve, Sunday, June 30, 2013 at 5:29pm
3x^2(4x2 + 1)^8 + 64x^4(4x2 + 1)^7
Notice that x^2 is a factor of each term, and so is a power of (4x^2+1)
So, factoring them out, we have
x^2 (4x^2+1)^7 (3(4x^2+1)+64x^2)
3(4x^2+1)+64x^2 = 12x^2+3+64x^2 = 76x^2+3
and that's Tony's answer
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