posted by Lynn on .
A dragster and driver together have mass 929.4 kg. The dragster, starting from rest, attains a speed of 26.5 m/s in 0.55s.
What is the size of the average force on the dragster during this time interval? Answer in units of N.
a=(V-Vo)/t = (26.5-0)/0.55 = 48.2 m/s^2.
F = m*a = 929.4 * 48.2 = 44,780 N.