p.82#18. if the quotient of a number and 6 is added to twice the number, the real result is 8 less than the number. find the number

n/6 + 2n = n-8

n = -48/7

That's an unexpected answer. What's this about "real result"?

d ko alam akala ko pa nmn pangsosolve

To find the number, let's first represent it as a variable. Let's call it 'x'.

According to the problem, the quotient of a number and 6 is added to twice the number, resulting in a value that is 8 less than the number itself.

We can write this information in the form of an equation:

(x / 6) + (2x) = x - 8

To solve this equation and find the value of 'x', we can follow these steps:

Step 1: Simplify the equation by combining like terms on both sides.
(x / 6) + (2x) = x - 8
Multiply both sides of the equation by 6 to eliminate the denominator:
6[(x / 6) + (2x)] = 6(x - 8)
x + 12x = 6x - 48

Step 2: Continue simplifying the equation.
Combining like terms on both sides:
13x = 6x - 48

Step 3: Get all the 'x' terms on one side of the equation.
Subtract 6x from both sides:
13x - 6x = 6x - 48 - 6x
7x = -48

Step 4: Solve for 'x' by dividing both sides by 7.
Divide both sides by 7:
(7x) / 7 = (-48) / 7
x = -48 / 7

So, the number is x = -48/7.