1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN.
ANS= MPa (Round to 3 decimal places)
Diameter = 33.000mm = 0.033m
30.000kN = 30000N
Area = pi*d^2/4
= 3.1416 * 0.033^2/ 4
= 3.1416 *0.001089/ 4
= 0.0034212024/ 4
= 8.553006*10^-4
= 0.0008553
Stress= Load/Area
= 30000/ 0.0008553
= 35075412.14Pa
= 35075.41214kPa
ANS = 35.07541214MPa
2) Consider that the rod was originally 1.000 meters long, and it was stretched 1.110mm by the pulling force. Calculate the strain produced in the rod.
ANS=(6decimal places)
1.110mm = 0.00111m
= 0.00111m/1m
ANS = 0.001110
Please check. Thank you.
To calculate the tensile stress in the rod, the first step is to calculate the area of the rod. The formula for the area of a circle is given by A = π * d^2 / 4, where A is the area and d is the diameter. In this case, the diameter is 33.000mm, which is equivalent to 0.033m.
A = π * (0.033^2) / 4
= π * 0.001089 / 4
= 0.0034212024 / 4
≈ 0.0008553
The next step is to calculate the stress using the formula Stress = Load / Area. The load in this case is 30.000kN, which is equivalent to 30000N.
Stress = 30000 / 0.0008553
≈ 35075412.14 Pa
≈ 35075.41214 kPa
ANS ≈ 35.07541214 MPa (rounded to 3 decimal places)
To calculate the strain produced in the rod, you need to know the original length of the rod and the change in length caused by the pulling force. Given that the original length is 1.000m and the rod was stretched by 1.110mm, you can calculate the strain using the formula Strain = Change in length / Original length.
Strain = 0.00111m / 1m
= 0.001110
ANS = 0.001110 (rounded to 6 decimal places)
Please note that the rounding was done in the final answers to the specified decimal places.