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September 20, 2014

September 20, 2014

Posted by **aris** on Saturday, June 29, 2013 at 7:39am.

- math 115a -
**Steve**, Saturday, June 29, 2013 at 4:08pmAs usual, draw a diagram.

A is farther away than B, so if B is x feet from the tower of height h,

h/x = tan46°

h/(x+80) = tan21°

or,

x = h cotn46° = h cot21° - 80

h = 80/(cot21°-cot46°) = 48.8 ft

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