Write the complex number in trigonometric form, using degree measure for the argument.

-12 - 16i

Hey, Tone, you've posted a bunch of these problems that are all just basically converting between rectangular and polar forms. I've done a few for you. What don't you get by now?

We're willing to help, but hate to be used to do someone's whole assignment. Post your efforts, and we can verify or redirect.

To write a complex number in trigonometric form, we first need to find the magnitude (or modulus) and argument (or angle) of the complex number.

The magnitude of a complex number is found using the formula:
|z| = sqrt(Re(z)^2 + Im(z)^2)

where Re(z) is the real part of the complex number and Im(z) is the imaginary part.

For the given complex number -12 - 16i, let's calculate the magnitude:
|z| = sqrt((-12)^2 + (-16)^2)
= sqrt(144 + 256)
= sqrt(400)
= 20

So, the magnitude (or modulus) of the complex number is 20.

The argument (or angle) of a complex number is found using the formula:
arg(z) = arctan(Im(z) / Re(z))

For the given complex number -12 - 16i, let's calculate the argument:
arg(z) = arctan((-16) / (-12))
= arctan(4/3)
≈ 53.13 degrees

Now, we can write the complex number -12 - 16i in trigonometric form using degree measure for the argument:
z = 20(cos(53.13°) + i*sin(53.13°))

So, the complex number -12 - 16i in trigonometric form is 20(cos(53.13°) + i*sin(53.13°)).