Posted by Matt on Friday, June 28, 2013 at 4:13pm.
I'm trying to create a macro that asks for a loan between 1 dollar and 5 million, and returns different interest rates based on the amount of the loan. For some reason when I type in different loan amounts it automatically makes my rate ".1", when it should be say ".08", or ".11" because of the entered loan amount.
Heres my code so far:
Sub DetermineinterestIf()
Dim loan As Variant
Dim interest As Double
Do
loan = InputBox("Enter your desired loan amount, from 1 dollar to 5 million dollars.")
Loop Until IsNumeric(loan)
If loan < 1000000 Then interest = ".08"
If loan > 4000000 Then interest = ".11"
If 1000000 < loan < 4000000 Then interest = ".10"
MsgBox ("The loan amount was " & loan & " with an interest rate of " & interest & ".")
End Sub
Any ideas where I have gone wrong?

VBA Programming  Steve, Friday, June 28, 2013 at 4:29pm
First off, why use strings to specify a numeric (Double) value for interest?
I learned VBA a while ago, but I think that
If 1000000 < loan < 4000000 Then interest = .10
is invalid syntax. Try
If (1000000 < loan) and (loan < 4000000) Then interest = .10
Or, you might try
interest = 0.10
If loan < 1000000 Then interest = .08
If loan > 4000000 Then interest = .11
That is, assume the interest will be .10, and only change it if the loan amount is too big or too small
Or, if you find that you have to do other stuff depending on the interest rate, you could go wholehog and say
If loan < 1000000 Then
interest = .08
do 8% stuff
Else If loan > 4000000 Then
interest = .11
do 11% stuff
Else
interest = .10
do 10% stuff
End If
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