# Physics (Stress & Strain)

posted by
**Danny** on
.

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced.

ANS 1 = kPa (3 decimal places)

ANS 2 = (6 decimal places)

1.000cm = 0.01m

2.900cm = 0.029m

length = 1m

Bar extension = 1.500mm = 0.0015m

Area = w * h

= 0.01 * 0.029

= 0.00029

Stress = Load/ Area

= 189000.000N/ 0.000290

= 651724137.9Pa

ANS = 651724.1379kPa

Strain = 0.0015/ 8.7

= 1.7241 * 10^-4

ANS = 0.000172

Please check. Thank you.