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In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The sys- tem has a small piston with a cross-sectional area of 0.063 m2 and a large piston with a cross-sectional area of 0.172 m2. An engine weighing 2800 N rests on the large piston.
What force must be applied to the small piston in order to lift the engine?
Answer in Newtons

  • Physics - ,

    pressureSmall=pressureLarge (pascal's principle)
    forceSmall/areaSmall=forceLarge/AreaLarge

    forceSmall=.063*2800/.172

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