Posted by **Danny** on Friday, June 28, 2013 at 1:01pm.

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm?

ANS = kN (Round to 3 decimal place)

Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6

Factor of Safety = 3.000

Rod diameter = 6.000cm = .06m

Allowable Strength

= Ultimate strength/ Factor of Safety

= 600* 10^6/ 3 = 200 * 10^6 (or)

= 600000000/3 = 200000000

Allowable Strength

= Load/ Area

Load

= Allowable Strength * Area

= Allowable Strength * (pi*d^2/4)

=600*10^6*pi*.06^2/4

=600000000*3.1416*.0036/4

=6785856/4

=1696464N

=1696.464kN

Please check. Thank you.

- Physics (Stress & Stain) -
**bobpursley**, Friday, June 28, 2013 at 7:38pm
no. you need to divide the max load by 3, somehow you dropped that.

- Physics (Stress & Stain) -
**Danny**, Friday, June 28, 2013 at 9:26pm
Load

= Allowable Strength * Area

= Allowable Strength * (pi*d^2/4)

=200*10^6*pi*.06^2/4

=200000000*3.1416*.0036/4

=2261952/4

=565488N

=565.488kN

Please check. Thank you.

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