Posted by tony on .
Use De Moivre's theorem to simplify the expression. Write the answer in a + bi form.
[2(cos 240° + i sin 240°)]^5

trig 
Count Iblis,
z = 2(cos 240° + i sin 240°) =
2 exp(4/3 pi i)
z^5 = 2^5 exp(20/3 pi i) =
32 exp(2/3 pi i) =
16 + 16 sqrt(3) i 
trig 
Steve,
(2cis240°)^5 = 2^5 cis(5*240°)
= 32 cis1200°
= 32 cis120°
= 16 + 16√3 i