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September 1, 2014

September 1, 2014

Posted by **tony** on Friday, June 28, 2013 at 12:08pm.

[2(cos 240° + i sin 240°)]^5

- trig -
**Count Iblis**, Friday, June 28, 2013 at 12:33pmz = 2(cos 240° + i sin 240°) =

2 exp(4/3 pi i)

z^5 = 2^5 exp(20/3 pi i) =

32 exp(2/3 pi i) =

-16 + 16 sqrt(3) i

- trig -
**Steve**, Friday, June 28, 2013 at 12:34pm(2cis240°)^5 = 2^5 cis(5*240°)

= 32 cis1200°

= 32 cis120°

= -16 + 16√3 i

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