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March 6, 2015

March 6, 2015

Posted by **Danny** on Friday, June 28, 2013 at 10:17am.

ANS = kN (Round to 3 decimal places)

ultimate strength = 550.000MPa

Factor of safety = 3.000

Rod diameter = 4.100cm = .041m

Not sure how to find the maximum permissible load for the rod. Need some help please. Thank you.

- Physics (Stress & Strain) -
**Elena**, Friday, June 28, 2013 at 11:11amFactor of safety = ultimate strength/allowable strength

Allowable strength= ultimate strength/ Factor of safety=

=550•10⁶/3=183.33•10⁶

Allowable strength=Load/Area =>

Load= Allowable strength x Area =

= Allowable strength x (π•d²/4)

=183.33•10⁶•π•0.041²/4=0.242•10⁶ N=

=242 kN

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