Physics (Stress & Strain)
posted by Danny on .
The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm?
ANS = kN (Round to 3 decimal places)
ultimate strength = 550.000MPa
Factor of safety = 3.000
Rod diameter = 4.100cm = .041m
Not sure how to find the maximum permissible load for the rod. Need some help please. Thank you.

Factor of safety = ultimate strength/allowable strength
Allowable strength= ultimate strength/ Factor of safety=
=550•10⁶/3=183.33•10⁶
Allowable strength=Load/Area =>
Load= Allowable strength x Area =
= Allowable strength x (π•d²/4)
=183.33•10⁶•π•0.041²/4=0.242•10⁶ N=
=242 kN