Math
posted by Tracy on .
In a survey of families in which both parents work, one of the questions asked was, "Have you refused a job, promotion, or transfer because it would mean less time with your family?" A total of 200 men and 200 women were asked this question. "Yes" was the response given by 34% of the men and 26% of the women. Based on this survey, can we conclude that there is a difference in the proportion of men and women responding "yes" at the 0.05 level of significance? (Use Men  Women.)
(a) Find z. (Give your answer correct to two decimal places.)
(ii) Find the pvalue. (Give your answer correct to four decimal places.)

z = 1.75
pvalue =.0809
If pvalue is greater than alpha
Fail to reject Ho
If pvalue is less than alpha
Reject Ho 
1. Men 2. Women
n1 = 200. n2 = 200
x1 = .34(200) =64. x2 = .26(200) = 52
phat1 = .34. phat2 = .26
pbar = (x1 + x2)/(n1+n2)
pbar = (68+52)/(200+200)
pbar = .30
qbar = 1pbar = .70
z = (phat1phat2)/sqrt(phar*qbar/n1 + pbar*qbar/n2)
z = (.34.26)/sqrt(.3*.7/200 + .3*.7/200)
z = + 1.7457
ti83
2nd vars
2normalcdf(10, 1. 7457) = = .04043
two tail so you multiply 2
2( .04043) = 0.08086
Four decimal places = .0809