Post a New Question

Math

posted by on .

How do i get 2 consecutive numbers (pair numbers) that they product is 272?
4X² + 4X - 272=0

  • Math - ,

    h, h +1

    h(h+1) = 272

    h^2 + h = 272

    h^2 + h -272 = 272-272

    h^2 + h -272 = 0

    (h -16)(h + 17) = 0

    h = 16
    h = -17

    -16, -17, and 16, 17

  • Math - ,

    x = first number

    y = second number

    y = x + 1


    x * y = 272

    x * ( x + 1 ) = 272

    x ^ 2 + x = 272

    x ^ 2 + x - 272 = 0

    Solutions :

    x = - 17

    and

    x = 16


    For x = - 17

    y = x + 1 = - 17 + 1 = - 16

    x * y = - 17 * ( - 16 ) = 272


    For x = 16

    y = x + 1 = 16 + 1 = 17

    x * y = 16 * 17 = 272


    So solutions are :

    - 17 and - 16

    and

    16 and 17

  • Math - ,

    Yes.Both are all solution.

    Proof

    x(x+1)= 272

    16(16+1) = 272
    16(17) =272
    272 = 272

    -17(-17+1) = 272

    -17(-16)= 272
    272 = 272

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question