Post a New Question


posted by .

Two 20.0-g ice cubes at –20.0 °C are placed into 295 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts.
Heat capacity of H2O(s)=37.7J
Heat capacity of H2O(l)=75.3J
Enthalpy of fusion of H2)=6.01kJ

  • Chemistry -

    heat to raise 40 g ice from -20 to zero.
    q1 = mass x specific heat x (Tfinal-Tinitial)

    heat to melt 40 g ice.
    q2 = mass ice x heat fusion (in joules)

    heat to raise melted water to final T.
    q3 = mass water x specific liquid water x (Tfinal-Tinitial)

    heat absorbed by 295 g H2O @ 25.0C
    q4 = mass H2O x specific heat liquid H2O x (Tfinal-Tinitial).
    q1 + q2 + q3 + q4 = 0
    Substitute and solve for Tfinal. Watch the signs.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question