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March 27, 2017

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Batman is standing on a cliff 120 m high. He is testing a new bat grappling hook. He
fires the hook with an initial velocity of 85 m/s at an angle of 45o
with respect to the
horizontal. How far from the base of the cliff (d) does the hook land?

  • physics - ,

    Vo = 85m/s[45o].
    Xo = 85*cos45 = 60.1 m/s.
    Yo = 85*sin45 = 60.1 m/s.

    Tr = (Y-Yo)/g = (o-60.1)/-9.8 = 6.1 s.
    = Rise time.

    h = Yo*t + 0.5g*t^2
    h = 60.1*6.1 - 4.9*(6.1)^2 = 184.3 m.

    d = Yo*t + 0.5g*t^2=184.3 + 120=304.3m
    0 + 4.9t^2 = 304.3
    t^2 = 62.1
    Tf = 7.9 s. = Fall time.

    d =Xo * (Tr + Tf)
    d = 60.1*(6.1+7.9) = 841.4 m.
















    91,75s = 105 m.

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