i want the answer just don't leave it upon me just giving the process..................................................................................................Two thin and identical steel rods move with equal speeds v=1 m/s in opposite directions and collide longitudinally.The collision is perfectly elastic and the rods swap their velocities. How long does the collision last in seconds if the length of the rods is l=30 cm. Assume that the speed of sound in the steel rods is c=5000 m/s?

0.00012

To find out how long the collision lasts, we need to determine the time it takes for the sound wave to travel through one of the rods.

First, let's calculate the length of one of the rods in meters by converting it from centimeters:
l = 30 cm = 0.3 m

Next, we can use the equation v = d/t, where v is the velocity of the sound wave, d is the distance traveled by the sound wave, and t is the time taken.

We know that the velocity of the sound wave in the steel rods is c = 5000 m/s. Therefore, we can rearrange the equation to solve for t:
t = d / v

Since the sound wave would travel through the entire length of the rod, the distance traveled by the sound wave is equal to the length of the rod:
d = l = 0.3 m

Now we can substitute the values into the equation to find the time taken for the sound wave to travel through one rod:
t = 0.3 m / 5000 m/s

Simplifying the expression:
t = 6 × 10^(-5) s

Therefore, the collision lasts for approximately 6 × 10^(-5) seconds.