Posted by **Julie** on Wednesday, June 26, 2013 at 2:50pm.

can someone tell me if I am correct

graph y1=(1/3)^x and y2= (1/3)^x+2

the relationships between the two graphs is they are separated horizontally by 2 units

- College Algebra -
**Steve**, Wednesday, June 26, 2013 at 2:59pm
no, they are separated vertically.

y1 = y2 - 2

To separate horizontally, you need the 2nd x to be 2 less than the first.

y1 = (1/3)^x

y2 = (1/3)^(x-2)

Since the new x-values are 2 less than the old ones, it's as if the y-axis had been shifted 2 units to the right.

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