Posted by **Avinash** on Wednesday, June 26, 2013 at 9:54am.

MR. x is invested a certain amount in debit and equity funds the ratio of 4:5 respectively,At the end of one year ,he earned a total dividend of 30% on his investment. After one year he reinvested the amount includeing dividend in the ratio 6:7 in debt and equity funds. Ifthe amount reinvested in Equity funds was RS 94,500, what was the original amount invested in Equity funds ?

1)75,000 2)81000 3)60000 4)65000 5)none of these

Ans is 1) i was tryed

2)if the length of rectangular field is increased by 20% and the breadth is reduced by 20% , the area of the rectangle will be 192 m^2 , what is the area of the orignal rectangle ?

1) 184 2)196 3)204 4)225 5)none of these

Ans is 5)

plz tell me how to do it

3) product of one-third of a number and 150% of another number is what percent of the product of original number ?

1) 80 2) 50 3) 75 4)120 5) none of these

Ans is 2)

plz post how to slove these questions by step wise

- maths -
**Steve**, Wednesday, June 26, 2013 at 11:38am
#1. The investment is divided into 9 parts, 4a and 5a.

The investment yielded 30%, so the amount reinvested was 9a*1.3 = 11.7a

Now, that amount is divided into 13 parts, 6b and 7b.

7b=94500

so, 6b = 81000

The amount reinvested was 175,500 = 11.7a

So, a = 15000

The original amount invested in Equity funds was 5a = 75,000

#2. If the original length is x and breadth is y,

(1.2x)(.8y)=192

.96xy = 192

The original area is xy, so it is 192/.96 = 200

#3. If the two numbers are x and y,

(x/3)(3/2 y) = 1/2 xy

so, it is 50% of the original product

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