MR. x is invested a certain amount in debit and equity funds the ratio of 4:5 respectively,At the end of one year ,he earned a total dividend of 30% on his investment. After one year he reinvested the amount includeing dividend in the ratio 6:7 in debt and equity funds. Ifthe amount reinvested in Equity funds was RS 94,500, what was the original amount invested in Equity funds ?

1)75,000 2)81000 3)60000 4)65000 5)none of these
Ans is 1) i was tryed

2)if the length of rectangular field is increased by 20% and the breadth is reduced by 20% , the area of the rectangle will be 192 m^2 , what is the area of the orignal rectangle ?
1) 184 2)196 3)204 4)225 5)none of these
Ans is 5)
plz tell me how to do it

3) product of one-third of a number and 150% of another number is what percent of the product of original number ?
1) 80 2) 50 3) 75 4)120 5) none of these
Ans is 2)
plz post how to slove these questions by step wise

#1. The investment is divided into 9 parts, 4a and 5a.

The investment yielded 30%, so the amount reinvested was 9a*1.3 = 11.7a

Now, that amount is divided into 13 parts, 6b and 7b.

7b=94500
so, 6b = 81000
The amount reinvested was 175,500 = 11.7a
So, a = 15000

The original amount invested in Equity funds was 5a = 75,000

#2. If the original length is x and breadth is y,

(1.2x)(.8y)=192
.96xy = 192
The original area is xy, so it is 192/.96 = 200

#3. If the two numbers are x and y,
(x/3)(3/2 y) = 1/2 xy
so, it is 50% of the original product

Let's break down each question and explain how to solve them step by step:

1) The question states that Mr. X has invested a certain amount in debt and equity funds in the ratio of 4:5. At the end of one year, he earned a total dividend of 30% on his investment. After one year, he reinvested the amount, including the dividend, in the ratio 6:7 in debt and equity funds. We are given that the amount reinvested in equity funds was Rs 94,500 and we need to find the original amount invested in equity funds.

To solve this problem, we will use the concept of ratios. Let's assume that the original investment in debt funds is 4x and the original investment in equity funds is 5x.

After one year, he earns a 30% dividend on his investment, which means the total amount at the end of the year, including the dividend, is 130% of the original investment.

The amount reinvested in debt funds is 6y and in equity funds is 7y, where y is the dividend amount.

We are told that the amount reinvested in equity funds was Rs 94,500. So, we can set up the equation:

7y = 94500

Solving for y, we find that y = 13500.

Now, since y is the dividend amount, the original investment in equity funds is 5x = 94500 - 13500 = Rs 81,000.

Therefore, the original amount invested in equity funds is Rs 81,000.

2) The question asks us to find the area of the original rectangle when the length is increased by 20% and the breadth is reduced by 20%. We are given that the new area is 192 m^2.

To solve this problem, we will use the concept of percentages. Let's assume the original length of the rectangle is x and the original breadth is y.

The new length is increased by 20%, which means it becomes 1.2 times the original length. So, the new length is 1.2x.

The new breadth is reduced by 20%, which means it becomes 0.8 times the original breadth. So, the new breadth is 0.8y.

The new area is the product of the new length and new breadth, which is (1.2x) * (0.8y) = 192.

Simplifying the equation, we get 0.96xy = 192.

To find the area of the original rectangle, we can divide the new area by 0.96:

Area of the original rectangle = 192 / 0.96 = 200 m^2.

Therefore, the area of the original rectangle is 200 m^2.

3) The question asks us to find the percentage of the product of one-third of a number and 150% of another number compared to the product of the original numbers.

Let's assume the first number is x and the second number is y.

One-third of the first number is (1/3)x, and 150% of the second number is (150/100)y = (3/2)y.

The product of one-third of the first number and 150% of the second number is [(1/3)x] * [(3/2)y] = (1/2)xy.

The product of the original numbers is xy.

To find the percentage, we divide the product of the first numbers by the product of the original numbers and then multiply by 100:

Percentage = [(1/2)xy / xy] * 100 = (1/2) * 100 = 50.

Therefore, the product of one-third of a number and 150% of another number is 50% of the product of the original number.