Wednesday

April 23, 2014

April 23, 2014

Posted by **tracy10** on Tuesday, June 25, 2013 at 10:40am.

n = 48, Ód = 238, Ód2 = 6202

(a) Find t. (Give your answer correct to two decimal places.)

(ii) Find the p-value. (Give your answer correct to four decimal places.)

- math -
**Kuai**, Tuesday, June 25, 2013 at 2:42pmSSd = 6202 - (238)^2/48

SSd = 5201.917

Sd = sqrt(SSd/n-1)

Sd = sqrt(5021.917/47) =

Sd = 10.337

t = 4.958/10.337/sqrt(48)

t = 3.323

Two tail = .0017

right tail = 8.6885e^-4

Left tail = .9991

- math -
**Tracy 10**, Tuesday, June 25, 2013 at 11:11pmHave a question, where did you get the 4.958 and what did you look at for it. Thanks this has really helped so far, just unsure on that.

- math -
**Kuai**, Wednesday, June 26, 2013 at 1:57pmThis is mean = 238/48 = 4.985

I am looking for t.

- math -
**Kuai**, Wednesday, June 26, 2013 at 2:17pmTypo

238/48 = 4.958

- math -
**Tracy**, Wednesday, June 26, 2013 at 4:49pmBut how do you get the p-value, I have worked it out by hand and also put into calculator and it comes up wrong. 0.0017 was the last answer I got. and 0.9991 before that. I have several questions like this asking for p-value so if you could work one out and I could use as an example I would appreciate it. Thank you for all your help. I got the t as 3.32 and that was the right answer on that one.

- math -
**Kuai**, Thursday, June 27, 2013 at 5:16pmFirst of all, you have to calculate your mean, standard deviation

sum of d is 238

n is 48

Mean = 238/48 = 4.958

Variance = 6202 -238^2/48 = 5201.92

standard derivation sqrt((variance/n-1)

Sd = 10.337

Find p-value you use your ti-83 plus

Go to stat

Tests

2-T-Test

Enter mean = 4.958

Go to down to Sx then

Standard deviation or sx = 10.337

n =48

Select Not equal

Go to down and select calculate enter

It will you info

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