SSd = 6202 - (238)^2/48
SSd = 5201.917
Sd = sqrt(SSd/n-1)
Sd = sqrt(5021.917/47) =
Sd = 10.337
t = 4.958/10.337/sqrt(48)
t = 3.323
Two tail = .0017
right tail = 8.6885e^-4
Left tail = .9991
Have a question, where did you get the 4.958 and what did you look at for it. Thanks this has really helped so far, just unsure on that.
This is mean = 238/48 = 4.985
I am looking for t.
238/48 = 4.958
But how do you get the p-value, I have worked it out by hand and also put into calculator and it comes up wrong. 0.0017 was the last answer I got. and 0.9991 before that. I have several questions like this asking for p-value so if you could work one out and I could use as an example I would appreciate it. Thank you for all your help. I got the t as 3.32 and that was the right answer on that one.
First of all, you have to calculate your mean, standard deviation
sum of d is 238
n is 48
Mean = 238/48 = 4.958
Variance = 6202 -238^2/48 = 5201.92
standard derivation sqrt((variance/n-1)
Sd = 10.337
Find p-value you use your ti-83 plus
Go to stat
Enter mean = 4.958
Go to down to Sx then
Standard deviation or sx = 10.337
Select Not equal
Go to down and select calculate enter
It will you info
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