Thursday

August 21, 2014

August 21, 2014

Posted by **James** on Tuesday, June 25, 2013 at 1:08am.

- Discreet math -
**MathMate**, Tuesday, June 25, 2013 at 7:10amIf you need a proof of the proposition/identity, please first double check the expressions.

[(pvq)^**(p=>)**^**(q=>)**]=>**r[**(pvq)^**(p=>)**^**(q=>)**]=>r

Not sure if something is missing where expression is indicated in bold. Perhaps there are other problems.

**Related Questions**

Math- Truth Tables - Construct a Truth Table for the given statement: 1. p ...

Math - Construct a Truth Table for the given statement: 1. p implies ~(pVq) 2...

Math- Truth Tables - Construct a Truth Table for the given statement: 1. p ...

Math - Construct a Truth Table for the given statement: 1. p implies ~(pVq) 2...

Math - Construct a Truth Table for the given statement: 1. p implies ~(pVq) 2...

geometry - Construct a truth table for (~PVq)___> q

geometry - Construct a truth table for (~pvq) ____>

truth tables - (pVq)--> ~p Construct a truth table

discrete mathematics with applications - A logical equivalance is derived from ...

discrete mathematics with applications - Determine which of the following pairs ...