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January 29, 2015

January 29, 2015

Posted by **James** on Tuesday, June 25, 2013 at 1:08am.

- Discreet math -
**MathMate**, Tuesday, June 25, 2013 at 7:10amIf you need a proof of the proposition/identity, please first double check the expressions.

[(pvq)^**(p=>)**^**(q=>)**]=>**r[**(pvq)^**(p=>)**^**(q=>)**]=>r

Not sure if something is missing where expression is indicated in bold. Perhaps there are other problems.

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