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November 29, 2014

November 29, 2014

Posted by **student** on Monday, June 24, 2013 at 3:09am.

must be tired cause my steps are not calculating correctly

- algebra -
**Steve**, Monday, June 24, 2013 at 4:52amwhat you should do is show how far you got, if you want help.

another root is necessarily 2+i, so

(x^2-4x+5) divides x^4-8x^3+64x-105

In fact,

x^4-8x^3+64x-105 = (x^2-4x+5)(x^2-4x-21)

Now it's a piece o' cake, no?

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