Tuesday

October 21, 2014

October 21, 2014

Posted by **Julie** on Monday, June 24, 2013 at 3:01am.

I know the conjucants are -i and -3i

(x-i)(x-3i) (x+i)(x=3i)

- College Algebra -
**Steve**, Monday, June 24, 2013 at 4:55amSo, multiply it out to get

f(x) = a(x^2+1)(x^2+9) = a(x^4+10x^2+9)

Now, f(-1) = a(1+10+9) = 20a, so we need a=3 and thus

f(x) = 3(x^4+10x^2+9)

BTW, that's "conjugates"

**Answer this Question**

**Related Questions**

College Algebra - OOPS I got the zeros wrong in the last post...please show work...

College Algebra - Find a polynomial of the specified degree that has the given ...

college algebra - form a polynomial f(x) with real coefficients having the given...

College Algebra - I'm supposed to find a polynomial with specified Zeros. This ...

College Algebra! help! - Form a polynomial f(x) with the real coefficients ...

College Algebra - Form a polynomial f(x) with real coefficients having the given...

College algebra - Form a polynomial f(x) with the real coefficients having the ...

College algebra - Form a polynomial f(x) with real coefficents having the given ...

college algebra - Form a polynomial, f(x), with real coefficients having the ...

college algebra - form a polynomial f (x) with real coefficients having the ...