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September 2, 2015

Homework Help: Physics (Stress & Strain)

Posted by Danny on Sunday, June 23, 2013 at 10:34pm.

What is the factory of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 61000.000N. The steel hanger in question has a cross sectional area of 6.500cm^2.
ANS = (Round to 3 decimal places)

6.500cm = 0.065m
Load = 61000.000N

Ultimate strength
= 630.000MPa = 630000000N

Factor of safety
= Ultimate stress/ allowable stress
= 630000000/61000
ANS = 10327.868

Is this done correctly?

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