Post a New Question

math/algebra

posted by on .

solve the equation

log2(3x-2) - log2 (x-5)=4

  • math/algebra - ,

    3x-2/x-5 = 2^4

    3x-2/x-5 = 16

    multiply by x-5

    x-5(3x-2/x-5) = 16(x-5)

    3x -2 = 16x -80

    3x -16x -2 16x-16x -80

    -13x -2 = -80

    -13x -2 + 2 = -80 +2

    -13x = -78

    x = 6

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question