Posted by tracy12 on Sunday, June 23, 2013 at 8:41pm.
The computerscience aptitude score, x, and the achievement score, y (measured by a comprehensive final), were measured for 10 students in a beginning computerscience course. The results were as follows. (Give your answers correct to two decimal places.)
x 7 10 19 9 20 22 6 13 18 15
y 29 27 28 33 24 15 25 23 21 18
(a) Find the equation of the line of best fit.
y hat = 0.56 + 1.78 x
(b) Find se2.
36.00

statistics check  Kuai, Sunday, June 23, 2013 at 9:58pm
Y hat = .57x + 32.20

statistics check  tracy12, Sunday, June 23, 2013 at 10:17pm
So what did I do wrong on the part b? That one is wrong also.

statistics check  Kuai, Sunday, June 23, 2013 at 10:20pm
What Do you mean se2

statistics check  Kuai, Sunday, June 23, 2013 at 10:30pm
What Do you mean by this se2

statistics check  tracy12, Sunday, June 23, 2013 at 10:49pm
I am sorry that is Se squared. That is the way it is written on the test.

statistics check  MathMate, Monday, June 24, 2013 at 5:54am
SE² is given by:
[ Σ(yyBar)^2  [Σ(xxBar)(yyBar)]²/Σ(xxBar)² ] /(n2)
I get:
Σ(yyBar)²=258.1
Σ(xxBar)(yyBar) = 168.7
Σ(xxBar)²=296.9
n=10
to get
se²=20.28

statistics check  tracy12, Monday, June 24, 2013 at 9:45am
I have a question where did you get 258.1. I must of had my numbers wrong, because I had those other two.

statistics check  MathMate, Monday, June 24, 2013 at 10:08am
I got it from summing (yyBar)^2, and I had yBar=24.3.

statistics check  tracy12, Monday, June 24, 2013 at 12:20pm
Ok, thank you, I had the wrong numbers for the yBar

statistics check :)  MathMate, Monday, June 24, 2013 at 1:05pm
You're welcome!
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