posted by louis aaaa on .
A skateboarder, starting from rest, rolls down a 13.4-m ramp. When she arrives at the bottom of the ramp her speed is 6.14 m/s. (a) Determine the magnitude of her acceleration, assumed to be constant. (b) If the ramp is inclined at 32.6 ° with respect to the ground, what is the component of her acceleration that is parallel to the ground?
a. V^2 = Vo^2 + 2a.d
a = (V^2-Vo^2)/2d.
a = (6.14-0)/26.8 = 0.229 m/s^2
b. a = 0.229*cos 32.6 = 0.193 m/s^2,