Posted by **Danny** on Sunday, June 23, 2013 at 1:47pm.

A uniform bar 1.900m in length and having a cross sectional area of 10.500cm^2 is subject to a loading of 5550.000N. This load causes an extension of the bar length of 1.100mm. Calculate the stress and strain produced.

Stress = Load/ Area

Strain = Change in length/ length

cross section = 10.500cm = 105mm

bar length = 1.100mm

Would I first need to solve for the Area? How do I find the Area? Help.

ANS 1 = kPa (round to 3 decimal places)

ANS 2 = (round to 6 decimal places)

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