I assume the last sentence is
"What is AD?" since AD2 does not mean much.
Use cosine rule to find ∠A, in triangle ABC.
= 59° (approx.)
Area of triangle ABC
Since AD is angle bisector, the altitudes of D to AB equals that to AC.
Therefore AD divides the area of triangle ABC in ratios of the bases AB and AC. Thus
Area of ΔADC=(33√39)*(24/(20+24))
Area of ΔADC can also be found by the trigonometric formula
Area of ΔADC
=AD*AC*sin(A/2) ... since AD bisects A
18√39 = AD * 24 *sin(A/2)
It is asking for the length of AD squared or AD^2.
The solution is given for AD.
Are you able to calculate AD²?
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