Thursday

January 29, 2015

January 29, 2015

Posted by **James** on Sunday, June 23, 2013 at 7:48am.

- Math 61 -
**Steve**, Sunday, June 23, 2013 at 6:54pmsince y^3 = 8x^2,

y = 2x^(2/3)

y' = 4/3 x^(-1/3)

y'^2 = 16/(9x^(2/3))

arc length is thus

∫[1,8] √(1+16/(9x^(2/3))) dx

u=x^-2/3

then let v = u^1/2

then let 4w = 3tanv

and you finally wind up with

1/27 √(9+16/x^2/3) (9x + 16x^1/3) [1,8]

= 1/27 ((√(9+4)(72+32))-(√(16+9)(9+16)))

= 1/27 (104√13 - 125)

**Answer this Question**

**Related Questions**

AP Calc B/C - Find the arc length of one arch of the sine curve. I started it by...

multivariable calc - Please help! Find the point where the curve r(t) = (12sint)...

Math Arc Length - Find the arc length corresponding to an angle of a degrees on ...

Math rem - 2.Find the length of the arc in a circle if the radius of the circle ...

MATH--Please help!! - I'm desperate! Find the point where the curve r(t)=(12sint...

calc 3 - find the arc length of the curve r(t)= <6sqrt(2),e^t,e^(-6t)>

math - Whats the difference between an arc [of a circle]'s length and measure? ...

Calculus - For the curve r = 2 sin 3(theta): Find the arc length of one petal

calculus - Can someone please help me find the arc length of this curve? x = 3y...

Calculus ll - Arc Length/Simpson's Rule - Use Simpson's Rule with n=10 to ...