Posted by **Satyam** on Sunday, June 23, 2013 at 2:19am.

Find the largest integer S which is a divisor of n^5−17n^3+16n for every integer n≥4. Tried it for a number of times. Please answer if you know how to solve it.

- Maths -
**MathMate**, Sunday, June 23, 2013 at 5:43am
In the given case, since the given polynomial is of the fifth degree, you only have to try S=1,2,3,4 and up to 5.

In fact:

Let's factor the polynomial

f(x)=n^5-17*n^3+16*n

=(n-4)*(n-1)*n*(n+1)*(n+4)

From this you will find the factors have the following properties:

if

n=0 (mod 4)

then

n=0 (mod 4) ... hypothesis

n-4=0 (mod 4)

n-1=3 (mod 4)

n+1=1 (mod 4)

n+2=2 (mod 4) since n=0 (mod 4)

Which means that if S=4, then

f(n) = 0 for all n≥4 since the factors have residues 0,1,2,3 when divided by 4.

## Answer This Question

## Related Questions

- Algebra - A.Write and solve an equation to find three consecutive integers with ...
- Algebra - A.Write and solve an equation to find three consecutive integers with ...
- math - For every positive integer n, consider all monic polynomials f(x) with ...
- heeeeeeelp math3 - For every positive integer n consider all polynomials f(x) ...
- heeeeeeeeelp math - For every positive integer n consider all polynomials f(x) ...
- heeeeeelp math - For every positive integer n, consider all polynomials f(x) ...
- heeeeeeelp math - For every positive integer n, consider all monic polynomials f...
- Math (algebra) - For every positive integer n, consider all monic polynomials f(...
- maths - The smallest of three consecutive integers is added to the largest, the ...
- maths - The smallest of three consecutive integers is added to the largest, the ...

More Related Questions