Posted by Ku on Sunday, June 23, 2013 at 1:44am.
Solve the exponential equation algebraically
5^(t/2) = 0.20

Precal  MathMate, Sunday, June 23, 2013 at 5:30am
5^(t/2)=0.20
take log on both sides,
(t/2)log(5)=log(0.20)
solve for t
t/2 = log(0.20)/log(5)
t=2log(0.20)/log(5)...isolate t
=log(1/0.04)/log(5)...absorb 2 into log(0.2)
=log(25)/log(5)... evaluate reciprocal
=2... laws of logarithm, 25=5²
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