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March 31, 2015

March 31, 2015

Posted by **Stacie** on Saturday, June 22, 2013 at 10:37pm.

Options:

A: y=7/3xz; 49

B: y=6/7xz; 18

C: y=14/3xz; 98

D: y=3/7xz; 9

- Algebra 2 -
**MathMate**, Sunday, June 23, 2013 at 7:37amLet

y=kxz

98/3=k(2*7)

k=98/3/14=7/3

Therefore y=(7/3)xz

when x=7, z=3

then y=(7/3)*7*3=49

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