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Posted by on Saturday, June 22, 2013 at 10:37pm.

y varies jointly as x and z, and y=98/3 when x=2 ans z=7. Find y when x=7 and z=3.

Options:

A: y=7/3xz; 49
B: y=6/7xz; 18
C: y=14/3xz; 98
D: y=3/7xz; 9

  • Algebra 2 - , Sunday, June 23, 2013 at 7:37am

    Let
    y=kxz
    98/3=k(2*7)
    k=98/3/14=7/3
    Therefore y=(7/3)xz
    when x=7, z=3
    then y=(7/3)*7*3=49

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