What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N.

The steel hanger in question has a cross sectional area of 7.600cm^2
ANS= Round to 3 decimal places

Safety factor = design load/ load
= 550.000MPa = 550000000Pa
= 550000000/ 64000
= 8593.75

tension design = 550MPa * 0.076M^2
= 18.000

Have I messed thing up? Please let me know if I am on the right track. Thanks.

550*10^6 Pa ultimate = 5.50*10^8 Pa

7.6 cm^2 /100/100 = 7.6*10^-4 m^2
(You only divided by 100 but it is squared so 10,000 cm^2/m^2

6.4 * 10^4 N/7.6*10^-4 m^2 = .842 *10^8 N/m^2 or Pascals real load

5.50*10^8/ .842*10^8 = 6.53