Posted by **Shin** on Saturday, June 22, 2013 at 3:08am.

5 distinct positive reals form an arithmetic progression. The 1st, 2nd and 5th term form a geometric progression. If the product of these 5 numbers is 124 4/9, what is the product of the 3 terms of the geometric progression?

Note: The phrase "form an arithmetic progression" means that the values are consecutive terms of an arithmetic progression. Similarly, "form a geometric progression" means that the values are consecutive terms of a geometric progression.

- Math (Geometric Progression) -
**Promise**, Wednesday, November 26, 2014 at 6:58am
U5=a t(n-1)d

- Math (Geometric Progression) -
**Anonymous**, Friday, March 20, 2015 at 3:06pm
123

## Answer This Question

## Related Questions

- Math - 5 distinct positive reals form an arithmetic progression. The 1st, 2nd ...
- Math - Three numbers form a geometric progression. If 4 is subtracted from the ...
- math - 1) If the number 1,1/3,1/9, are terms of Geometric progression. Find its ...
- math - The sum of the 3 terms in arithmetic sequence is 39.if these numbers is ...
- Math - The third, fifth and seventeenth terms of an arithmetic progression are ...
- Arithmetic - The first, second and third terms of a geometric progression are 2k...
- math - The first, the third and the seventh terms of an increasing arithmetic ...
- Maths - 1..The first 2 terms of a geometric progression are the same as the ...
- Geometric progression - The second term of a geometric progression is 12 more ...
- MATHEMATIC DEPARTMENT - The second, third and ninth terms of an arithmetic ...

More Related Questions