posted by Sue7 on .
Consider the approximately normal population of heights of male college students with mean ì = 69 inches and standard deviation of ó = 4.6 inches. A random sample of 25 heights is obtained.
(b) Find the proportion of male college students whose height is greater than 69 inches. (Give your answer correct to four decimal places.)
(e) Find P(x > 70). (Give your answer correct to four decimal places.) 0.1587 was my answer .
(f) Find P(x < 67). (Give your answer correct to four decimal places.) 0.0228
was my answer .
b) mean = median = mode. See definition of median.
e) Z = (score-mean)/SD for raw scores. Answer wrong.
Z = (score-mean)/SEm for means. Answer wrong.
SEm = SD/√n = 4.6/√25 = 4.6/5 = .92
f) Use same process.
Use Table indicated in later post.
I understand the median is when you arrange the numbers from small to large and it is the middle number. If I write down 1-69, middle number is 35 but the answer ask for it in four decimal places and that answer is wrong and (e) and (f). e I came up with 0.001 and (f) I am not really sure of.