Friday

September 19, 2014

September 19, 2014

Posted by **anonymous** on Friday, June 21, 2013 at 1:47am.

g0(x)=x; gk+1(x)=gk(x^2+2x)−gk(x)

Find the last three digits of the coefficient of x^2 in g299(x).

- math -
**Alestair**, Saturday, June 22, 2013 at 6:18am941

- math -
**anonymous**, Saturday, June 22, 2013 at 8:19amsorry, but wrong answer...

repeating the question again ->

A sequence of polynomials gk(x) is defined recursively as follows:

g0(x)=x

gk+1(x)=gk(x^2+2x)−gk(x)

Find the last three digits of the coefficient of x^2 in g299(x).

- math -
**Danny**, Saturday, June 22, 2013 at 11:52am634

- math -
**debjit**, Saturday, June 22, 2013 at 11:55amThat's wrong. I thint, that should be 925.

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