Posted by anonymous on Friday, June 21, 2013 at 1:47am.
A sequence of polynomials gk(x) is defined recursively as follows.
g0(x)=x; gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).

math  Alestair, Saturday, June 22, 2013 at 6:18am
941

math  anonymous, Saturday, June 22, 2013 at 8:19am
sorry, but wrong answer...
repeating the question again >
A sequence of polynomials gk(x) is defined recursively as follows:
g0(x)=x
gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).

math  Danny, Saturday, June 22, 2013 at 11:52am
634

math  debjit, Saturday, June 22, 2013 at 11:55am
That's wrong. I thint, that should be 925.
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