Wednesday
April 1, 2015

Homework Help: Physics

Posted by ALex on Thursday, June 20, 2013 at 10:00pm.

A q = +3.00 mC test charge is placed inside a constant uniform electric field created in a parallel plate capacitor connected to a battery of unknown voltage.

The capacitor is made of two parallel plates each with area equal to 0.250 m2 separated by a distance of 0.0400 m and with no dielectric other than vacuum. The permitivitty of vacuum is 8.85e-12 C2/Nm2.

a) If it takes 0.0320 N of force to hold the charge the stationary between the plates, what is the value of the electric field in the capacitor?
b) What is the change of potential energy of the test charge moves without assistance from one plate to the other? (note: "+" would indicated a GAIN in potential energy)
c) Through what change in voltage did the test charge move?
d) What is the voltage of the battery that charged the capacitor?
e) What is the capacitance of the capacitor in picofarads?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

College Physics - A 12.0- A 12.0- A 12.0-V battery remains connected to a ...
Physics - A parallel plate capacitor has a rectangular plates with length 5cm ...
physics parallel plate - A proton traveling at a speed 1.0*106 m/s of enters the...
HELP dielectric - Energy of a Capacitor in the Presence of a Dielectric A ...
Physics - A parallel plate capacitor with plate separation d is connected to a ...
physics - Which of the statements regarding this situation are true? Select all ...
physics please help!! - A parallel plate capacitor with plate separation d is ...
physic - A dielectric-filled parallel-plate capacitor has plate area A = 10.0cm2...
Physics - A parallel plate capacitor with plate separation d is connected to a ...
Physics - A parallel plate capacitor with plate separation d is connected to a ...

Members